let n be non zero Nat; for l, m being Nat st l + m <= (2 to_power n) - 1 holds
add_ovfl ((n -BinarySequence l),(n -BinarySequence m)) = FALSE
let l, m be Nat; ( l + m <= (2 to_power n) - 1 implies add_ovfl ((n -BinarySequence l),(n -BinarySequence m)) = FALSE )
set L = n -BinarySequence l;
set M = n -BinarySequence m;
A1:
(Absval ((n -BinarySequence l) + (n -BinarySequence m))) + (2 to_power n) >= 2 to_power n
by NAT_1:11;
assume A2:
l + m <= (2 to_power n) - 1
; add_ovfl ((n -BinarySequence l),(n -BinarySequence m)) = FALSE
then A3:
l < 2 to_power n
by Th8;
assume
add_ovfl ((n -BinarySequence l),(n -BinarySequence m)) <> FALSE
; contradiction
then A4:
IFEQ ((add_ovfl ((n -BinarySequence l),(n -BinarySequence m))),FALSE,0,(2 to_power n)) = 2 to_power n
by FUNCOP_1:def 8;
A5:
m < 2 to_power n
by A2, Th8;
(Absval ((n -BinarySequence l) + (n -BinarySequence m))) + (IFEQ ((add_ovfl ((n -BinarySequence l),(n -BinarySequence m))),FALSE,0,(2 to_power n))) =
(Absval (n -BinarySequence l)) + (Absval (n -BinarySequence m))
by BINARITH:21
.=
l + (Absval (n -BinarySequence m))
by A3, BINARI_3:35
.=
l + m
by A5, BINARI_3:35
;
hence
contradiction
by A2, A4, A1, XREAL_1:146, XXREAL_0:2; verum