let i, j, m, n be Nat; for X being BCK-algebra of i,j,m,n st i <= m & i < n holds
X is BCK-algebra of i,j,i,i + 1
let X be BCK-algebra of i,j,m,n; ( i <= m & i < n implies X is BCK-algebra of i,j,i,i + 1 )
assume that
A1:
i <= m
and
A2:
i < n
; X is BCK-algebra of i,j,i,i + 1
for x, y being Element of X holds Polynom (i,j,x,y) = Polynom (i,(i + 1),y,x)
proof
(
n - i is
Element of
NAT &
n - i > i - i )
by A2, NAT_1:21, XREAL_1:9;
then
n - i >= 1
by NAT_1:14;
then A3:
(n - i) + i >= 1
+ i
by XREAL_1:6;
let x,
y be
Element of
X;
Polynom (i,j,x,y) = Polynom (i,(i + 1),y,x)
A4:
i + 1
< n + 1
by A2, XREAL_1:6;
A5:
(
Polynom (
i,
j,
x,
y)
= Polynom (
m,
n,
y,
x) & (
((y,(y \ x)) to_power (m + 1)),
(x \ y))
to_power (i + 1) = (
((y,(y \ x)) to_power (m + 1)),
(x \ y))
to_power (n + 1) )
by Def3, Th19;
( (
y,
(y \ x))
to_power (i + 1) = (
y,
(y \ x))
to_power (n + 1) &
m + 1
>= i + 1 )
by A1, Th19, XREAL_1:6;
then
(
y,
(y \ x))
to_power (i + 1) = (
y,
(y \ x))
to_power (m + 1)
by A4, Th6;
hence
Polynom (
i,
j,
x,
y)
= Polynom (
i,
(i + 1),
y,
x)
by A4, A5, A3, Th6;
verum
end;
hence
X is BCK-algebra of i,j,i,i + 1
by Def3; verum