let i, j, m, n be Nat; for X being BCK-algebra of i,j,m,n st i <= m & j <= n holds
X is BCK-algebra of i,j,i,j
let X be BCK-algebra of i,j,m,n; ( i <= m & j <= n implies X is BCK-algebra of i,j,i,j )
assume that
A1:
i <= m
and
A2:
j <= n
; X is BCK-algebra of i,j,i,j
A3:
for x, y being Element of X holds Polynom (i,j,x,y) <= Polynom (i,j,y,x)
proof
let x,
y be
Element of
X;
Polynom (i,j,x,y) <= Polynom (i,j,y,x)
i + 1
<= m + 1
by A1, XREAL_1:6;
then A4:
(
((y,(y \ x)) to_power (m + 1)),
(x \ y))
to_power n <= (
((y,(y \ x)) to_power (i + 1)),
(x \ y))
to_power n
by Th5, BCIALG_2:19;
(
Polynom (
i,
j,
x,
y)
= Polynom (
m,
n,
y,
x) & (
((y,(y \ x)) to_power (i + 1)),
(x \ y))
to_power n <= (
((y,(y \ x)) to_power (i + 1)),
(x \ y))
to_power j )
by A2, Def3, Th5;
hence
Polynom (
i,
j,
x,
y)
<= Polynom (
i,
j,
y,
x)
by A4, Th1;
verum
end;
for x, y being Element of X holds Polynom (i,j,y,x) = Polynom (i,j,x,y)
proof
let x,
y be
Element of
X;
Polynom (i,j,y,x) = Polynom (i,j,x,y)
Polynom (
i,
j,
x,
y)
<= Polynom (
i,
j,
y,
x)
by A3;
then A5:
(Polynom (i,j,x,y)) \ (Polynom (i,j,y,x)) = 0. X
;
Polynom (
i,
j,
y,
x)
<= Polynom (
i,
j,
x,
y)
by A3;
then
(Polynom (i,j,y,x)) \ (Polynom (i,j,x,y)) = 0. X
;
hence
Polynom (
i,
j,
y,
x)
= Polynom (
i,
j,
x,
y)
by A5, BCIALG_1:def 7;
verum
end;
hence
X is BCK-algebra of i,j,i,j
by Def3; verum