let i, j, m, n be Nat; for X being BCK-algebra of i,j,m,n st i = min (i,j,m,n) & i = j holds
X is BCK-algebra of i,i,i,i
let X be BCK-algebra of i,j,m,n; ( i = min (i,j,m,n) & i = j implies X is BCK-algebra of i,i,i,i )
assume A1:
i = min (i,j,m,n)
; ( not i = j or X is BCK-algebra of i,i,i,i )
assume A2:
i = j
; X is BCK-algebra of i,i,i,i
A3:
for x, y being Element of X holds Polynom (i,i,x,y) <= Polynom (i,i,y,x)
proof
let x,
y be
Element of
X;
Polynom (i,i,x,y) <= Polynom (i,i,y,x)
i <= n
by A1, Th25;
then A4:
(
((y,(y \ x)) to_power (i + 1)),
(x \ y))
to_power n <= (
((y,(y \ x)) to_power (i + 1)),
(x \ y))
to_power i
by Th5;
i <= m
by A1, Th25;
then
i + 1
<= m + 1
by XREAL_1:6;
then A5:
(
((y,(y \ x)) to_power (m + 1)),
(x \ y))
to_power n <= (
((y,(y \ x)) to_power (i + 1)),
(x \ y))
to_power n
by Th5, BCIALG_2:19;
Polynom (
i,
j,
x,
y)
= Polynom (
m,
n,
y,
x)
by Def3;
hence
Polynom (
i,
i,
x,
y)
<= Polynom (
i,
i,
y,
x)
by A2, A5, A4, Th1;
verum
end;
for x, y being Element of X holds Polynom (i,i,y,x) = Polynom (i,i,x,y)
proof
let x,
y be
Element of
X;
Polynom (i,i,y,x) = Polynom (i,i,x,y)
Polynom (
i,
i,
x,
y)
<= Polynom (
i,
i,
y,
x)
by A3;
then A6:
(Polynom (i,i,x,y)) \ (Polynom (i,i,y,x)) = 0. X
;
Polynom (
i,
i,
y,
x)
<= Polynom (
i,
i,
x,
y)
by A3;
then
(Polynom (i,i,y,x)) \ (Polynom (i,i,x,y)) = 0. X
;
hence
Polynom (
i,
i,
y,
x)
= Polynom (
i,
i,
x,
y)
by A6, BCIALG_1:def 7;
verum
end;
hence
X is BCK-algebra of i,i,i,i
by Def3; verum