let i, j, m, n be Nat; ( i = min (i,j,m,n) implies ( i <= j & i <= m & i <= n ) )
A1:
min (m,n) <= n
by XXREAL_0:17;
assume
i = min (i,j,m,n)
; ( i <= j & i <= m & i <= n )
then A2:
( i <= min (i,j) & i <= min (m,n) )
by XXREAL_0:17;
( min (i,j) <= j & min (m,n) <= m )
by XXREAL_0:17;
hence
( i <= j & i <= m & i <= n )
by A2, A1, XXREAL_0:2; verum