let n be Nat; for X being BCK-algebra
for x, y being Element of X holds
( x \ y <= x & (x,y) to_power (n + 1) <= (x,y) to_power n )
let X be BCK-algebra; for x, y being Element of X holds
( x \ y <= x & (x,y) to_power (n + 1) <= (x,y) to_power n )
let x, y be Element of X; ( x \ y <= x & (x,y) to_power (n + 1) <= (x,y) to_power n )
(((x,y) to_power n) \ y) \ ((x,y) to_power n) =
(((x,y) to_power n) \ ((x,y) to_power n)) \ y
by BCIALG_1:7
.=
y `
by BCIALG_1:def 5
.=
0. X
by BCIALG_1:def 8
;
then A1:
((x,y) to_power n) \ y <= (x,y) to_power n
;
(x \ y) \ x =
(x \ x) \ y
by BCIALG_1:7
.=
y `
by BCIALG_1:def 5
.=
0. X
by BCIALG_1:def 8
;
hence
( x \ y <= x & (x,y) to_power (n + 1) <= (x,y) to_power n )
by A1, BCIALG_2:4; verum