let X be BCI-algebra; for x, y being Element of X
for n, m being Nat holds (((x,y) to_power n),y) to_power m = (x,y) to_power (n + m)
let x, y be Element of X; for n, m being Nat holds (((x,y) to_power n),y) to_power m = (x,y) to_power (n + m)
let n, m be Nat; (((x,y) to_power n),y) to_power m = (x,y) to_power (n + m)
defpred S1[ set ] means for m1 being Nat st m1 = $1 & m1 <= n holds
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m);
now for k being Nat st ( for m1 being Nat st m1 = k & m1 <= n holds
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m) ) holds
for m1 being Nat st m1 = k + 1 & m1 <= n holds
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m)let k be
Nat;
( ( for m1 being Nat st m1 = k & m1 <= n holds
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m) ) implies for m1 being Nat st m1 = k + 1 & m1 <= n holds
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m) )assume A1:
for
m1 being
Nat st
m1 = k &
m1 <= n holds
(
((x,y) to_power m1),
y)
to_power m = (
x,
y)
to_power (m1 + m)
;
for m1 being Nat st m1 = k + 1 & m1 <= n holds
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m)let m1 be
Nat;
( m1 = k + 1 & m1 <= n implies (((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m) )assume that A2:
m1 = k + 1
and A3:
m1 <= n
;
(((x,y) to_power m1),y) to_power m = (x,y) to_power (m1 + m)
k <= n
by A2, A3, NAT_1:13;
then
(
((x,y) to_power k),
y)
to_power m = (
x,
y)
to_power (k + m)
by A1;
then
((((x,y) to_power k),y) to_power m) \ y = (
x,
y)
to_power ((k + m) + 1)
by Th4;
then
(
(((x,y) to_power k) \ y),
y)
to_power m = (
x,
y)
to_power ((k + m) + 1)
by Th7;
hence
(
((x,y) to_power m1),
y)
to_power m = (
x,
y)
to_power (m1 + m)
by A2, Th4;
verum end;
then A4:
for k being Nat st S1[k] holds
S1[k + 1]
;
A5:
S1[ 0 ]
by Th1;
for n being Nat holds S1[n]
from NAT_1:sch 2(A5, A4);
hence
(((x,y) to_power n),y) to_power m = (x,y) to_power (n + m)
; verum