let n be Ordinal; for o being TermOrder of n st ( for a, b, c being bag of n st [a,b] in o holds
[(a + c),(b + c)] in o ) & o is_strongly_connected_in Bags n holds
Graded o is admissible
let o be TermOrder of n; ( ( for a, b, c being bag of n st [a,b] in o holds
[(a + c),(b + c)] in o ) & o is_strongly_connected_in Bags n implies Graded o is admissible )
assume that
A1:
for a, b, c being bag of n st [a,b] in o holds
[(a + c),(b + c)] in o
and
A2:
o is_strongly_connected_in Bags n
; Graded o is admissible
now for x, y being object st x in Bags n & y in Bags n & not [x,y] in Graded o holds
[y,x] in Graded olet x,
y be
object ;
( x in Bags n & y in Bags n & not [x,y] in Graded o implies [b2,b1] in Graded o )assume that A3:
x in Bags n
and A4:
y in Bags n
;
( not [x,y] in Graded o implies [b2,b1] in Graded o )reconsider x9 =
x,
y9 =
y as
bag of
n by A3, A4;
assume A5:
not
[x,y] in Graded o
;
[b2,b1] in Graded othen A6:
TotDegree x9 >= TotDegree y9
by A1, Def7;
end;
hence
Graded o is_strongly_connected_in Bags n
; BAGORDER:def 5 ( ( for a being bag of n holds [(EmptyBag n),a] in Graded o ) & ( for a, b, c being bag of n st [a,b] in Graded o holds
[(a + c),(b + c)] in Graded o ) )
hence
for a being bag of n holds [(EmptyBag n),a] in Graded o
; for a, b, c being bag of n st [a,b] in Graded o holds
[(a + c),(b + c)] in Graded o
hence
for a, b, c being bag of n st [a,b] in Graded o holds
[(a + c),(b + c)] in Graded o
; verum