set Q = LexOrder (I,R);
let a, b be object ; RELAT_2:def 5,RELAT_2:def 13 ( not a in field (LexOrder (I,R)) or not b in field (LexOrder (I,R)) or not [a,b] in LexOrder (I,R) or not [b,a] in LexOrder (I,R) )
assume
( a in field (LexOrder (I,R)) & b in field (LexOrder (I,R)) )
; ( not [a,b] in LexOrder (I,R) or not [b,a] in LexOrder (I,R) )
assume A1:
( [a,b] in LexOrder (I,R) & [b,a] in LexOrder (I,R) )
; contradiction
then reconsider a = a, b = b as Element of I * by ZFMISC_1:87;
set c = a;