let a be Real; ( 1 < a implies seq_a^ (a,1,0) is increasing )
assume AS:
1 < a
; seq_a^ (a,1,0) is increasing
C1:
for n being Element of NAT holds (seq_a^ (a,1,0)) . n < (seq_a^ (a,1,0)) . (n + 1)
proof
let n be
Element of
NAT ;
(seq_a^ (a,1,0)) . n < (seq_a^ (a,1,0)) . (n + 1)
L2:
(seq_a^ (a,1,0)) . n =
a to_power ((1 * n) + 0)
by ASYMPT_1:def 1
.=
a to_power n
;
(seq_a^ (a,1,0)) . (n + 1) =
a to_power ((1 * (n + 1)) + 0)
by ASYMPT_1:def 1
.=
a to_power (n + 1)
;
hence
(seq_a^ (a,1,0)) . n < (seq_a^ (a,1,0)) . (n + 1)
by L2, LC5aa, AS;
verum
end;
reconsider S = seq_a^ (a,1,0) as Real_Sequence ;
for n being Nat holds S . n < S . (n + 1)
hence
seq_a^ (a,1,0) is increasing
by SEQM_3:def 6; verum