let x be Element of RAT+ ; for i being ordinal Element of RAT+ st i < x & x < i + one holds
not x in omega
let i be ordinal Element of RAT+ ; ( i < x & x < i + one implies not x in omega )
assume that
A1:
i < x
and
A2:
x < i + one
and
A3:
x in omega
; contradiction
consider z being Element of RAT+ such that
A4:
i + one = x + z
by A2, Def13;
i + one = i +^ 1
by Th58;
then
i + one in omega
by Th31;
then reconsider z9 = z as Element of omega by A3, A4, Th71;
consider y being Element of RAT+ such that
A5:
x = i + y
by A1, Def13;
i in omega
by Th31;
then reconsider y9 = y as Element of omega by A3, A5, Th71;
i + one = i + (y + z)
by A5, A4, Th51;
then 1 =
y + z
by Th62
.=
y9 +^ z9
by Th58
;
then
y9 c= 1
by ORDINAL3:24;
then
( y = {} or y = 1 )
by ORDINAL3:16;
then
( i = x or i + one = x )
by A5, Th50;
hence
contradiction
by A1, A2; verum