let X, G be set ; for B being non empty finite Subset-Family of X st B is (B1) & B is (B2) & G is_generator-set_of B holds
/\-IRR B c= G \/ {X}
let B be non empty finite Subset-Family of X; ( B is (B1) & B is (B2) & G is_generator-set_of B implies /\-IRR B c= G \/ {X} )
assume that
A1:
( B is (B1) & B is (B2) )
and
A2:
G is_generator-set_of B
; /\-IRR B c= G \/ {X}
A3:
B = { (Intersect S) where S is Subset-Family of X : S c= G }
by A2;
A4:
G c= B
by A2;
let x be object ; TARSKI:def 3 ( not x in /\-IRR B or x in G \/ {X} )
assume A5:
x in /\-IRR B
; x in G \/ {X}
then reconsider xx = x as Element of B ;
A6:
xx is_/\-irreducible_in B
by A5, Def3;
assume A7:
not x in G \/ {X}
; contradiction
then
not x in {X}
by XBOOLE_0:def 3;
then A8:
x <> X
by TARSKI:def 1;
x in B
by A5;
then consider S being Subset-Family of X such that
A9:
x = Intersect S
and
A10:
S c= G
by A3;
not x in S
by A10, A7, XBOOLE_0:def 3;
hence
contradiction
by A1, A4, A9, A10, A8, A6, Th4, XBOOLE_1:1; verum