let R be domRing; for n being non empty Ordinal
for X being Subset of (Funcs (n,([#] R))) holds
( X = {} iff Ideal_ X = [#] (Polynom-Ring (n,R)) )
let n be non empty Ordinal; for X being Subset of (Funcs (n,([#] R))) holds
( X = {} iff Ideal_ X = [#] (Polynom-Ring (n,R)) )
let X be Subset of (Funcs (n,([#] R))); ( X = {} iff Ideal_ X = [#] (Polynom-Ring (n,R)) )
A1:
( X = {} implies Ideal_ X = [#] (Polynom-Ring (n,R)) )
( Ideal_ X = [#] (Polynom-Ring (n,R)) implies X = {} (Funcs (n,([#] R))) )
proof
assume A4:
Ideal_ X = [#] (Polynom-Ring (n,R))
;
X = {} (Funcs (n,([#] R)))
assume
X <> {} (Funcs (n,([#] R)))
;
contradiction
then consider o being
object such that A6:
o in X
by XBOOLE_0:def 1;
reconsider x =
o as
Element of
Funcs (
n,
([#] R))
by A6;
A7:
Ideal_ {x} = [#] (Polynom-Ring (n,R))
by A4, Th29, A6, ZFMISC_1:31;
reconsider y =
x as
Function of
n,
R ;
1. (Polynom-Ring (n,R)) in [#] (Polynom-Ring (n,R))
by SUBSET_1:def 1;
then
1_ (
n,
R)
in { f where f is Polynomial of n,R : {x} c= Zero_ f }
by A7, POLYNOM1:31;
then consider g being
Polynomial of
n,
R such that A9:
(
g = 1_ (
n,
R) &
{x} c= Zero_ g )
;
{x} c= {} (Funcs (n,([#] R)))
by A9, Th14;
hence
contradiction
;
verum
end;
hence
( X = {} iff Ideal_ X = [#] (Polynom-Ring (n,R)) )
by A1; verum