let X1, X2 be Subset of Q; ( ( for y being Element of Q holds
( y in X1 iff for x, z being Element of Q holds (x * y) * z = x * (y * z) ) ) & ( for y being Element of Q holds
( y in X2 iff for x, z being Element of Q holds (x * y) * z = x * (y * z) ) ) implies X1 = X2 )
assume that
A3:
for x being Element of Q holds
( x in X1 iff S2[x] )
and
A4:
for x being Element of Q holds
( x in X2 iff S2[x] )
; X1 = X2
thus
X1 = X2
from SUBSET_1:sch 2(A3, A4); verum