let d1, d2 be Element of D; :: thesis: ( ( b is having_a_unity & len F = 0 & d1 = the_unity_wrt b & d2 = the_unity_wrt b implies d1 = d2 ) & ( ( not b is having_a_unity or not len F = 0 ) & ex f being sequence of D st
( f . 0 = F . 0 & ( for n being Nat st n + 1 < len F holds
f . (n + 1) = b . ((f . n),(F . (n + 1))) ) & d1 = f . ((len F) - 1) ) & ex f being sequence of D st
( f . 0 = F . 0 & ( for n being Nat st n + 1 < len F holds
f . (n + 1) = b . ((f . n),(F . (n + 1))) ) & d2 = f . ((len F) - 1) ) implies d1 = d2 ) )

thus ( b is having_a_unity & len F = 0 & d1 = the_unity_wrt b & d2 = the_unity_wrt b implies d1 = d2 ) ; :: thesis: ( ( not b is having_a_unity or not len F = 0 ) & ex f being sequence of D st
( f . 0 = F . 0 & ( for n being Nat st n + 1 < len F holds
f . (n + 1) = b . ((f . n),(F . (n + 1))) ) & d1 = f . ((len F) - 1) ) & ex f being sequence of D st
( f . 0 = F . 0 & ( for n being Nat st n + 1 < len F holds
f . (n + 1) = b . ((f . n),(F . (n + 1))) ) & d2 = f . ((len F) - 1) ) implies d1 = d2 )

A26: ((len F) - 1) + 1 = len F ;
assume ( not b is having_a_unity or len F <> 0 ) ; :: thesis: ( for f being sequence of D holds
( not f . 0 = F . 0 or ex n being Nat st
( n + 1 < len F & not f . (n + 1) = b . ((f . n),(F . (n + 1))) ) or not d1 = f . ((len F) - 1) ) or for f being sequence of D holds
( not f . 0 = F . 0 or ex n being Nat st
( n + 1 < len F & not f . (n + 1) = b . ((f . n),(F . (n + 1))) ) or not d2 = f . ((len F) - 1) ) or d1 = d2 )

then 0 < len F by A2;
then A27: (len F) - 1 is Element of NAT by NAT_1:20;
given f1 being sequence of D such that A28: f1 . 0 = F . 0 and
A29: for n being Nat st n + 1 < len F holds
f1 . (n + 1) = b . ((f1 . n),(F . (n + 1))) and
A30: d1 = f1 . ((len F) - 1) ; :: thesis: ( for f being sequence of D holds
( not f . 0 = F . 0 or ex n being Nat st
( n + 1 < len F & not f . (n + 1) = b . ((f . n),(F . (n + 1))) ) or not d2 = f . ((len F) - 1) ) or d1 = d2 )

given f2 being sequence of D such that A31: f2 . 0 = F . 0 and
A32: for n being Nat st n + 1 < len F holds
f2 . (n + 1) = b . ((f2 . n),(F . (n + 1))) and
A33: d2 = f2 . ((len F) - 1) ; :: thesis: d1 = d2
defpred S1[ Nat] means ( $1 + 1 <= len F implies f1 . $1 = f2 . $1 );
A34: for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be Nat; :: thesis: ( S1[n] implies S1[n + 1] )
assume A35: S1[n] ; :: thesis: S1[n + 1]
assume (n + 1) + 1 <= len F ; :: thesis: f1 . (n + 1) = f2 . (n + 1)
then A36: n + 1 < len F by NAT_1:13;
then f2 . (n + 1) = b . ((f2 . n),(F . (n + 1))) by A32;
hence f1 . (n + 1) = f2 . (n + 1) by A29, A35, A36; :: thesis: verum
end;
A37: S1[ 0 ] by A28, A31;
for n being Nat holds S1[n] from NAT_1:sch 2(A37, A34);
hence d1 = d2 by A30, A33, A26, A27; :: thesis: verum