let AP be AffinPlane; ( AP is translational iff AP is satisfying_des_1 )
hereby ( AP is satisfying_des_1 implies AP is translational )
assume A1:
AP is
translational
;
AP is satisfying_des_1 thus
AP is
satisfying_des_1
verumproof
let A be
Subset of
AP;
AFF_2:def 12 for P, C being Subset of AP
for a, b, c, a9, b9, c9 being Element of AP st A // P & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A <> P & A <> C & a,b // a9,b9 & a,c // a9,c9 & b,c // b9,c9 & not LIN a,b,c & c <> c9 holds
A // Clet P,
C be
Subset of
AP;
for a, b, c, a9, b9, c9 being Element of AP st A // P & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A <> P & A <> C & a,b // a9,b9 & a,c // a9,c9 & b,c // b9,c9 & not LIN a,b,c & c <> c9 holds
A // Clet a,
b,
c,
a9,
b9,
c9 be
Element of
AP;
( A // P & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A <> P & A <> C & a,b // a9,b9 & a,c // a9,c9 & b,c // b9,c9 & not LIN a,b,c & c <> c9 implies A // C )
assume that A2:
A // P
and A3:
a in A
and A4:
a9 in A
and A5:
b in P
and A6:
b9 in P
and A7:
(
c in C &
c9 in C )
and A8:
A is
being_line
and A9:
P is
being_line
and A10:
C is
being_line
and A11:
A <> P
and A12:
A <> C
and A13:
a,
b // a9,
b9
and A14:
a,
c // a9,
c9
and A15:
b,
c // b9,
c9
and A16:
not
LIN a,
b,
c
and A17:
c <> c9
;
A // C
assume A18:
not
A // C
;
contradiction
consider K being
Subset of
AP such that A19:
c9 in K
and A20:
A // K
by A8, AFF_1:49;
A21:
a <> c
by A16, AFF_1:7;
A22:
not
a,
c // K
proof
assume
a,
c // K
;
contradiction
then
a,
c // A
by A20, AFF_1:43;
then A23:
c in A
by A3, A8, AFF_1:23;
a9,
c9 // a,
c
by A14, AFF_1:4;
then
a9,
c9 // A
by A3, A8, A21, A23, AFF_1:27;
then
c9 in A
by A4, A8, AFF_1:23;
hence
contradiction
by A7, A8, A10, A12, A17, A23, AFF_1:18;
verum
end;
A24:
A <> K
proof
assume A25:
A = K
;
contradiction
a9,
c9 // a,
c
by A14, AFF_1:4;
then
a9 = c9
by A4, A19, A20, A22, A25, AFF_1:32, AFF_1:40;
then
a9,
b9 // b,
c
by A15, AFF_1:4;
then
(
a9 = b9 or
a,
b // b,
c )
by A13, AFF_1:5;
then
(
b9 in A or
b,
a // b,
c )
by A4, AFF_1:4;
then
LIN b,
a,
c
by A2, A6, A11, AFF_1:45, AFF_1:def 1;
hence
contradiction
by A16, AFF_1:6;
verum
end;
A26:
now not b9 = c9assume
b9 = c9
;
contradictionthen
(
a,
b // a,
c or
a9 = b9 )
by A13, A14, AFF_1:5;
hence
contradiction
by A2, A4, A6, A11, A16, AFF_1:45, AFF_1:def 1;
verum end;
A27:
K is
being_line
by A20, AFF_1:36;
then consider x being
Element of
AP such that A28:
x in K
and A29:
LIN a,
c,
x
by A22, AFF_1:59;
a,
c // a,
x
by A29, AFF_1:def 1;
then
a,
x // a9,
c9
by A14, A21, AFF_1:5;
then
b,
x // b9,
c9
by A1, A2, A3, A4, A5, A6, A8, A9, A11, A13, A19, A20, A27, A28, A24;
then
(
b,
x // b,
c or
b9 = c9 )
by A15, AFF_1:5;
then
LIN b,
x,
c
by A26, AFF_1:def 1;
then A30:
LIN x,
c,
b
by AFF_1:6;
A31:
LIN x,
c,
c
by AFF_1:7;
LIN x,
c,
a
by A29, AFF_1:6;
then
c in K
by A16, A28, A30, A31, AFF_1:8;
hence
contradiction
by A7, A10, A17, A18, A19, A20, A27, AFF_1:18;
verum
end;
end;
assume A32:
AP is satisfying_des_1
; AP is translational
let A be Subset of AP; AFF_2:def 11 for P, C being Subset of AP
for a, b, c, a9, b9, c9 being Element of AP st A // P & A // C & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A <> P & A <> C & a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9
let P, C be Subset of AP; for a, b, c, a9, b9, c9 being Element of AP st A // P & A // C & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A <> P & A <> C & a,b // a9,b9 & a,c // a9,c9 holds
b,c // b9,c9
let a, b, c, a9, b9, c9 be Element of AP; ( A // P & A // C & a in A & a9 in A & b in P & b9 in P & c in C & c9 in C & A is being_line & P is being_line & C is being_line & A <> P & A <> C & a,b // a9,b9 & a,c // a9,c9 implies b,c // b9,c9 )
assume that
A33:
A // P
and
A34:
A // C
and
A35:
a in A
and
A36:
a9 in A
and
A37:
b in P
and
A38:
b9 in P
and
A39:
c in C
and
A40:
c9 in C
and
A41:
A is being_line
and
A42:
P is being_line
and
A43:
C is being_line
and
A44:
A <> P
and
A45:
A <> C
and
A46:
a,b // a9,b9
and
A47:
a,c // a9,c9
; b,c // b9,c9
A48:
a <> b
by A33, A35, A37, A44, AFF_1:45;
A49:
a9 <> b9
by A33, A36, A38, A44, AFF_1:45;
set K = Line (a,c);
set N = Line (b9,c9);
A50:
a <> c
by A34, A35, A39, A45, AFF_1:45;
then A51:
a in Line (a,c)
by AFF_1:24;
assume A52:
not b,c // b9,c9
; contradiction
then A53:
b9 <> c9
by AFF_1:3;
then A54:
b9 in Line (b9,c9)
by AFF_1:24;
A55:
b <> c
by A52, AFF_1:3;
A56:
not LIN a,b,c
proof
assume A57:
LIN a,
b,
c
;
contradiction
then
LIN b,
c,
a
by AFF_1:6;
then
b,
c // b,
a
by AFF_1:def 1;
then
b,
c // a,
b
by AFF_1:4;
then A58:
b,
c // a9,
b9
by A46, A48, AFF_1:5;
LIN c,
b,
a
by A57, AFF_1:6;
then
c,
b // c,
a
by AFF_1:def 1;
then
b,
c // a,
c
by AFF_1:4;
then
b,
c // a9,
c9
by A47, A50, AFF_1:5;
then
a9,
c9 // a9,
b9
by A55, A58, AFF_1:5;
then
LIN a9,
c9,
b9
by AFF_1:def 1;
then
LIN b9,
c9,
a9
by AFF_1:6;
then
b9,
c9 // b9,
a9
by AFF_1:def 1;
then
b9,
c9 // a9,
b9
by AFF_1:4;
hence
contradiction
by A52, A49, A58, AFF_1:5;
verum
end;
A59:
c in Line (a,c)
by A50, AFF_1:24;
A60:
Line (b9,c9) is being_line
by A53, AFF_1:24;
then consider M being Subset of AP such that
A61:
b in M
and
A62:
Line (b9,c9) // M
by AFF_1:49;
A63:
c9 in Line (b9,c9)
by A53, AFF_1:24;
A64:
a9 <> c9
by A34, A36, A40, A45, AFF_1:45;
A65:
not LIN a9,b9,c9
proof
assume
LIN a9,
b9,
c9
;
contradiction
then
a9,
b9 // a9,
c9
by AFF_1:def 1;
then
a,
b // a9,
c9
by A46, A49, AFF_1:5;
then
a,
b // a,
c
by A47, A64, AFF_1:5;
hence
contradiction
by A56, AFF_1:def 1;
verum
end;
A66:
not Line (a,c) // M
proof
assume
Line (
a,
c)
// M
;
contradiction
then
Line (
a,
c)
// Line (
b9,
c9)
by A62, AFF_1:44;
then
a,
c // b9,
c9
by A51, A59, A54, A63, AFF_1:39;
then
a9,
c9 // b9,
c9
by A47, A50, AFF_1:5;
then
c9,
a9 // c9,
b9
by AFF_1:4;
then
LIN c9,
a9,
b9
by AFF_1:def 1;
hence
contradiction
by A65, AFF_1:6;
verum
end;
A67:
Line (a,c) is being_line
by A50, AFF_1:24;
A68:
M is being_line
by A62, AFF_1:36;
then consider x being Element of AP such that
A69:
x in Line (a,c)
and
A70:
x in M
by A67, A66, AFF_1:58;
A71:
b,x // b9,c9
by A54, A63, A61, A62, A70, AFF_1:39;
set D = Line (x,c9);
A72:
A <> Line (x,c9)
A73:
x in Line (x,c9)
by AFF_1:15;
LIN a,c,x
by A67, A51, A59, A69, AFF_1:21;
then
a,c // a,x
by AFF_1:def 1;
then A74:
a,x // a9,c9
by A47, A50, AFF_1:5;
A75:
c9 in Line (x,c9)
by AFF_1:15;
A76:
not LIN a,b,x
proof
A77:
a <> x
proof
assume
a = x
;
contradiction
then
a,
b // b9,
c9
by A54, A63, A61, A62, A70, AFF_1:39;
then
a9,
b9 // b9,
c9
by A46, A48, AFF_1:5;
then
b9,
a9 // b9,
c9
by AFF_1:4;
then
LIN b9,
a9,
c9
by AFF_1:def 1;
hence
contradiction
by A65, AFF_1:6;
verum
end;
assume
LIN a,
b,
x
;
contradiction
then
LIN x,
b,
a
by AFF_1:6;
then A78:
x,
b // x,
a
by AFF_1:def 1;
x <> b
by A67, A51, A59, A56, A69, AFF_1:21;
hence
contradiction
by A67, A51, A61, A68, A66, A69, A70, A78, A77, AFF_1:38;
verum
end;
A79:
P // C
by A33, A34, AFF_1:44;
A80:
x <> c9
proof
A81:
now not P = Line (b9,c9)A82:
P // P
by A33, AFF_1:44;
assume A83:
P = Line (
b9,
c9)
;
contradictionthen
c in P
by A39, A40, A79, A63, AFF_1:45;
hence
contradiction
by A37, A38, A52, A63, A83, A82, AFF_1:39;
verum end;
assume
x = c9
;
contradiction
then
M = Line (
b9,
c9)
by A63, A62, A70, AFF_1:45;
then A84:
(
P = Line (
b9,
c9) or
b = b9 )
by A37, A38, A42, A60, A54, A61, AFF_1:18;
then
b,
a // b,
a9
by A46, A81, AFF_1:4;
then
LIN b,
a,
a9
by AFF_1:def 1;
then
LIN a,
a9,
b
by AFF_1:6;
then
(
b in A or
a = a9 )
by A35, A36, A41, AFF_1:25;
then
LIN a9,
c,
c9
by A33, A37, A44, A47, AFF_1:45, AFF_1:def 1;
then
LIN c,
c9,
a9
by AFF_1:6;
then
(
c = c9 or
a9 in C )
by A39, A40, A43, AFF_1:25;
hence
contradiction
by A34, A36, A45, A52, A84, A81, AFF_1:2, AFF_1:45;
verum
end;
then
Line (x,c9) is being_line
by AFF_1:24;
then
A // Line (x,c9)
by A32, A33, A35, A36, A37, A38, A41, A42, A44, A46, A71, A74, A73, A75, A80, A76, A72;
then
Line (x,c9) // C
by A34, AFF_1:44;
then
C = Line (x,c9)
by A40, A75, AFF_1:45;
then
C = Line (a,c)
by A39, A43, A52, A67, A59, A69, A71, A73, AFF_1:18;
hence
contradiction
by A34, A35, A45, A51, AFF_1:45; verum