let a, b, n be Nat; ( a < b implies Ackermann (a,n) < Ackermann (b,n) )
defpred S1[ Nat] means for a being Nat st a < $1 holds
H1(a,n) < H1($1,n);
A1:
S1[ 0 ]
;
A2:
for k being Nat st S1[k] holds
S1[k + 1]
proof
let k be
Nat;
( S1[k] implies S1[k + 1] )
assume A3:
S1[
k]
;
S1[k + 1]
let a be
Nat;
( a < k + 1 implies H1(a,n) < H1(k + 1,n) )
assume
a < k + 1
;
H1(a,n) < H1(k + 1,n)
then
a <= k
by NAT_1:13;
end;
for k being Nat holds S1[k]
from NAT_1:sch 2(A1, A2);
hence
( a < b implies Ackermann (a,n) < Ackermann (b,n) )
; verum