let X1, X2 be Subset of Q; ( ( for x being Element of Q holds
( x in X1 iff for y, z being Element of Q holds (x * y) * z = x * (y * z) ) ) & ( for x being Element of Q holds
( x in X2 iff for y, z being Element of Q holds (x * y) * z = x * (y * z) ) ) implies X1 = X2 )
assume that
A1:
for x being Element of Q holds
( x in X1 iff S1[x] )
and
A2:
for x being Element of Q holds
( x in X2 iff S1[x] )
; X1 = X2
thus
X1 = X2
from SUBSET_1:sch 2(A1, A2); verum