let a, m be Nat; for F, G being FinSequence of NAT holds (a * (F ^ G)) mod m = ((a * F) mod m) ^ ((a * G) mod m)
let F, G be FinSequence of NAT ; (a * (F ^ G)) mod m = ((a * F) mod m) ^ ((a * G) mod m)
A1:
F is FinSequence of REAL
by FINSEQ_2:24, NUMBERS:19;
A2:
G is FinSequence of REAL
by FINSEQ_2:24, NUMBERS:19;
reconsider FG = F ^ G as FinSequence of NAT ;
A3:
FG is FinSequence of REAL
by FINSEQ_2:24, NUMBERS:19;
A4: dom (a * (F ^ G)) =
Seg (len (a * FG))
by FINSEQ_1:def 3
.=
Seg (len FG)
by A3, NEWTON:2
.=
dom (F ^ G)
by FINSEQ_1:def 3
;
A5: dom (a * G) =
Seg (len (a * G))
by FINSEQ_1:def 3
.=
Seg (len G)
by A2, NEWTON:2
.=
dom G
by FINSEQ_1:def 3
;
A6: dom ((a * G) mod m) =
Seg (len ((a * G) mod m))
by FINSEQ_1:def 3
.=
Seg (len (a * G))
by Def1
.=
Seg (len G)
by A2, NEWTON:2
.=
dom G
by FINSEQ_1:def 3
;
A7: dom (a * F) =
Seg (len (a * F))
by FINSEQ_1:def 3
.=
Seg (len F)
by A1, NEWTON:2
.=
dom F
by FINSEQ_1:def 3
;
A8: dom ((a * F) mod m) =
Seg (len ((a * F) mod m))
by FINSEQ_1:def 3
.=
Seg (len (a * F))
by Def1
.=
Seg (len F)
by A1, NEWTON:2
.=
dom F
by FINSEQ_1:def 3
;
A9:
for x being object st x in dom (F ^ G) holds
((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . x
proof
reconsider H =
F ^ G as
FinSequence of
NAT ;
let x be
object ;
( x in dom (F ^ G) implies ((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . x )
assume A10:
x in dom (F ^ G)
;
((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . x
then reconsider x =
x as
Element of
NAT ;
now ((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . xper cases
( x in dom F or ex n being Nat st
( n in dom G & x = (len F) + n ) )
by A10, FINSEQ_1:25;
suppose
ex
n being
Nat st
(
n in dom G &
x = (len F) + n )
;
((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . xthen consider n being
Element of
NAT such that A13:
n in dom G
and A14:
x = (len F) + n
;
A15:
((a * (F ^ G)) mod m) . x =
((a * (F ^ G)) . x) mod m
by A4, A10, Def1
.=
(a * (H . x)) mod m
by RVSUM_1:44
.=
(a * (G . n)) mod m
by A13, A14, FINSEQ_1:def 7
;
len ((a * F) mod m) =
len (a * F)
by Def1
.=
len F
by A1, NEWTON:2
;
then (((a * F) mod m) ^ ((a * G) mod m)) . x =
((a * G) mod m) . n
by A6, A13, A14, FINSEQ_1:def 7
.=
((a * G) . n) mod m
by A5, A13, Def1
.=
(a * (G . n)) mod m
by RVSUM_1:44
;
hence
((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . x
by A15;
verum end; end; end;
hence
((a * (F ^ G)) mod m) . x = (((a * F) mod m) ^ ((a * G) mod m)) . x
;
verum
end;
A16: dom ((a * (F ^ G)) mod m) =
Seg (len ((a * FG) mod m))
by FINSEQ_1:def 3
.=
Seg (len (a * FG))
by Def1
.=
Seg (len FG)
by A3, NEWTON:2
.=
dom (F ^ G)
by FINSEQ_1:def 3
;
dom (((a * F) mod m) ^ ((a * G) mod m)) =
Seg (len (((a * F) mod m) ^ ((a * G) mod m)))
by FINSEQ_1:def 3
.=
Seg ((len ((a * F) mod m)) + (len ((a * G) mod m)))
by FINSEQ_1:22
.=
Seg ((len (a * F)) + (len ((a * G) mod m)))
by Def1
.=
Seg ((len (a * F)) + (len (a * G)))
by Def1
.=
Seg ((len F) + (len (a * G)))
by A1, NEWTON:2
.=
Seg ((len F) + (len G))
by A2, NEWTON:2
.=
Seg (len (F ^ G))
by FINSEQ_1:22
.=
dom (F ^ G)
by FINSEQ_1:def 3
;
hence
(a * (F ^ G)) mod m = ((a * F) mod m) ^ ((a * G) mod m)
by A16, A9; verum