let X be set ; for Y being non empty set
for E1, E2 being Subset of [:X,Y:]
for p being set st E1 c= E2 holds
X-section (E1,p) c= X-section (E2,p)
let Y be non empty set ; for E1, E2 being Subset of [:X,Y:]
for p being set st E1 c= E2 holds
X-section (E1,p) c= X-section (E2,p)
let E1, E2 be Subset of [:X,Y:]; for p being set st E1 c= E2 holds
X-section (E1,p) c= X-section (E2,p)
let p be set ; ( E1 c= E2 implies X-section (E1,p) c= X-section (E2,p) )
assume A1:
E1 c= E2
; X-section (E1,p) c= X-section (E2,p)
hence
X-section (E1,p) c= X-section (E2,p)
; verum