let a, b be Real; ( a < 0 & a < b implies b / a < 1 )
assume A1:
a < 0
; ( not a < b or b / a < 1 )
assume A2:
a < b
; b / a < 1
assume
b / a >= 1
; contradiction
then
(b / a) * a <= 1 * a
by A1, Lm28;
hence
contradiction
by A1, A2, XCMPLX_1:87; verum