let a, b be Real; ( 0 < a & b < a implies b / a < 1 )
assume A1:
a > 0
; ( not b < a or b / a < 1 )
assume A2:
b < a
; b / a < 1
assume
b / a >= 1
; contradiction
then
(b / a) * a >= 1 * a
by A1, Lm12;
hence
contradiction
by A1, A2, XCMPLX_1:87; verum