reconsider xx = x as setbyTARSKI:1;
not xx in xx
; hence
( ( x in y implies a is object ) & ( x = y implies b is object ) & ( not x in y & not x = y implies c is object ) & ( for b1 being object st x in y & x = y holds ( b1= a iff b1= b ) ) )
byTARSKI:1; :: thesis: verum