let X be set ; for g being SimpleGraph of X
for v being set
for vg being finite set st vg = the carrier of g & v in vg & 1 + (degree (g,v)) = card vg holds
for w being Element of vg st v <> w holds
ex e being set st
( e in the SEdges of g & e = {v,w} )
let g be SimpleGraph of X; for v being set
for vg being finite set st vg = the carrier of g & v in vg & 1 + (degree (g,v)) = card vg holds
for w being Element of vg st v <> w holds
ex e being set st
( e in the SEdges of g & e = {v,w} )
let v be set ; for vg being finite set st vg = the carrier of g & v in vg & 1 + (degree (g,v)) = card vg holds
for w being Element of vg st v <> w holds
ex e being set st
( e in the SEdges of g & e = {v,w} )
let vg be finite set ; ( vg = the carrier of g & v in vg & 1 + (degree (g,v)) = card vg implies for w being Element of vg st v <> w holds
ex e being set st
( e in the SEdges of g & e = {v,w} ) )
assume that
A1:
vg = the carrier of g
and
A2:
v in vg
and
A3:
1 + (degree (g,v)) = card vg
; for w being Element of vg st v <> w holds
ex e being set st
( e in the SEdges of g & e = {v,w} )
vg is Subset of X
by A1, Th21;
then reconsider X = X as non empty set by A2;
let w be Element of vg; ( v <> w implies ex e being set st
( e in the SEdges of g & e = {v,w} ) )
assume A4:
v <> w
; ex e being set st
( e in the SEdges of g & e = {v,w} )
take
{v,w}
; ( {v,w} in the SEdges of g & {v,w} = {v,w} )
hereby {v,w} = {v,w}
now {v,w} in the SEdges of gconsider ww being
finite set such that A5:
ww = { vv where vv is Element of X : ( vv in vg & {v,vv} in the SEdges of g ) }
and A6:
degree (
g,
v)
= card ww
by A1, Th28;
reconsider wwv =
ww \/ {v} as
finite set ;
assume A7:
not
{v,w} in the
SEdges of
g
;
contradictionA8:
( not
v in ww & not
w in ww )
proof
assume
w in ww
;
contradiction
then
ex
vv being
Element of
X st
(
w = vv &
vv in vg &
{v,vv} in the
SEdges of
g )
by A5;
hence
contradiction
by A7;
verum
end; A9:
now for e being set st e in ww holds
e in vglet e be
set ;
( e in ww implies e in vg )assume
e in ww
;
e in vgthen
ex
vv being
Element of
X st
(
e = vv &
vv in vg &
{v,vv} in the
SEdges of
g )
by A5;
hence
e in vg
;
verum end;
(
wwv c= vg &
wwv <> vg )
then A12:
wwv c< vg
by XBOOLE_0:def 8;
card wwv = 1
+ (card ww)
by A8, CARD_2:41;
hence
contradiction
by A3, A6, A12, CARD_2:48;
verum end; hence
{v,w} in the
SEdges of
g
;
verum
end;
thus
{v,w} = {v,w}
; verum