let X be set ; :: thesis: for B being SetSequence of X holds superior_setsequence B is V49()
let B be SetSequence of X; :: thesis: superior_setsequence B is V49()
now :: thesis: for n being Element of NAT holds (superior_setsequence B) . (n + 1) c= (superior_setsequence B) . nend;
hence superior_setsequence B is V49() by PROB_2:6; :: thesis: verum