let G, x be set ; ( card (union G) = 1 implies G is pairfree )
assume A:
card (union G) = 1
; G is pairfree
assume
not G is pairfree
; contradiction
then
PairsOf G <> {}
by Ledgeless;
then consider e being set such that
C:
e in PairsOf G
by XBOOLE_0:def 1;
consider x, y being set such that
D:
x <> y
and
E:
x in union G
and
F:
y in union G
and
e = {x,y}
by C, SG4;
consider w being set such that
H:
union G = {w}
by A, CARD_2:42;
x = w
by E, H, TARSKI:def 1;
hence
contradiction
by D, F, H, TARSKI:def 1; verum