reconsider II = I as initial preProgram of SCM+FSA ;
let k1, k2 be Element of NAT ; ( IC (Comput ((P +* I),(Initialize s),k1)) = card I & ( for n being Element of NAT st not IC (Comput ((P +* I),(Initialize s),n)) in dom I holds
k1 <= n ) & IC (Comput ((P +* I),(Initialize s),k2)) = card I & ( for n being Element of NAT st not IC (Comput ((P +* I),(Initialize s),n)) in dom I holds
k2 <= n ) implies k1 = k2 )
assume that
A2:
IC (Comput ((P +* I),(Initialize s),k1)) = card I
and
A3:
( ( for n being Element of NAT st not IC (Comput ((P +* I),(Initialize s),n)) in dom I holds
k1 <= n ) & IC (Comput ((P +* I),(Initialize s),k2)) = card I )
and
A4:
for n being Element of NAT st not IC (Comput ((P +* I),(Initialize s),n)) in dom I holds
k2 <= n
; k1 = k2
A5:
now not k2 < k1assume
k2 < k1
;
contradictionthen
card II in dom II
by A3;
hence
contradiction
;
verum end;
now not k1 < k2assume
k1 < k2
;
contradictionthen
card II in dom II
by A2, A4;
hence
contradiction
;
verum end;
hence
k1 = k2
by A5, XXREAL_0:1; verum