let y be Element of X4; ( y = x `2 iff for x1, x2, x3, x4 being set st x = [x1,x2,x3,x4] holds
y = x4 )
thus
( y = x `4_4 implies for x1, x2, x3, x4 being set st x = [x1,x2,x3,x4] holds
y = x4 )
( ( for x1, x2, x3, x4 being set st x = [x1,x2,x3,x4] holds
y = x4 ) implies y = x `2 )proof
assume Z:
y = x `4_4
;
for x1, x2, x3, x4 being set st x = [x1,x2,x3,x4] holds
y = x4
let x1,
x2,
x3,
x4 be
set ;
( x = [x1,x2,x3,x4] implies y = x4 )
assume W:
x = [x1,x2,x3,x4]
;
y = x4
[x1,x2,x3,x4] `4_4 = x4
;
hence
y = x4
by W, Z;
verum
end;
assume Z:
for x1, x2, x3, x4 being set st x = [x1,x2,x3,x4] holds
y = x4
; y = x `2
consider xx1 being Element of X1, xx2 being Element of X2, xx3 being Element of X3, xx4 being Element of X4 such that
A6:
x = [xx1,xx2,xx3,xx4]
by Lm3;
[xx1,xx2,xx3,xx4] `4_4 = xx4
;
hence
y = x `4_4
by Z, A6; verum