let y be Element of X3; ( y = x `2 iff for x1, x2, x3 being set st x = [x1,x2,x3] holds
y = x3 )
thus
( y = x `3_3 implies for x1, x2, x3 being set st x = [x1,x2,x3] holds
y = x3 )
( ( for x1, x2, x3 being set st x = [x1,x2,x3] holds
y = x3 ) implies y = x `2 )proof
assume Z:
y = x `3_3
;
for x1, x2, x3 being set st x = [x1,x2,x3] holds
y = x3
let x1,
x2,
x3 be
set ;
( x = [x1,x2,x3] implies y = x3 )
assume W:
x = [x1,x2,x3]
;
y = x3
[x1,x2,x3] `3_3 = x3
;
hence
y = x3
by W, Z;
verum
end;
assume Z:
for x1, x2, x3 being set st x = [x1,x2,x3] holds
y = x3
; y = x `2
consider xx1 being Element of X1, xx2 being Element of X2, xx3 being Element of X3 such that
A6:
x = [xx1,xx2,xx3]
by Lm2;
[xx1,xx2,xx3] `3_3 = xx3
;
hence
y = x `3_3
by Z, A6; verum