let seq, seq1 be Complex_Sequence; ( seq is convergent & ex k being Element of NAT st seq = seq1 ^\ k implies seq1 is convergent )
assume that
A1:
seq is convergent
and
A2:
ex k being Element of NAT st seq = seq1 ^\ k
; seq1 is convergent
consider k being Element of NAT such that
A3:
seq = seq1 ^\ k
by A2;
consider g1 being Element of COMPLEX such that
A4:
for p being Real st 0 < p holds
ex n being Element of NAT st
for m being Element of NAT st n <= m holds
|.((seq . m) - g1).| < p
by A1, COMSEQ_2:def 5;
take g = g1; COMSEQ_2:def 5 for b1 being Element of REAL holds
( b1 <= 0 or ex b2 being Element of NAT st
for b3 being Element of NAT holds
( not b2 <= b3 or not b1 <= |.K65((seq1 . b3),g).| ) )
let p be Real; ( p <= 0 or ex b1 being Element of NAT st
for b2 being Element of NAT holds
( not b1 <= b2 or not p <= |.K65((seq1 . b2),g).| ) )
assume
0 < p
; ex b1 being Element of NAT st
for b2 being Element of NAT holds
( not b1 <= b2 or not p <= |.K65((seq1 . b2),g).| )
then consider n1 being Element of NAT such that
A5:
for m being Element of NAT st n1 <= m holds
|.((seq . m) - g1).| < p
by A4;
take n = n1 + k; for b1 being Element of NAT holds
( not n <= b1 or not p <= |.K65((seq1 . b1),g).| )
let m be Element of NAT ; ( not n <= m or not p <= |.K65((seq1 . m),g).| )
assume A6:
n <= m
; not p <= |.K65((seq1 . m),g).|
then consider l being Nat such that
A7:
m = (n1 + k) + l
by NAT_1:10;
reconsider l = l as Element of NAT by ORDINAL1:def 12;
m - k = ((n1 + l) + k) + (- k)
by A7;
then consider m1 being Element of NAT such that
A8:
m1 = m - k
;
now n1 <= m1assume
not
n1 <= m1
;
contradictionthen
m1 + k < n1 + k
by XREAL_1:6;
hence
contradiction
by A6, A8;
verum end;
then A9:
|.((seq . m1) - g1).| < p
by A5;
m1 + k = m
by A8;
hence
|.((seq1 . m) - g).| < p
by A3, A9, NAT_1:def 3; verum