let x, y, X be set ; ( {x,y} \ X = {x} iff ( not x in X & ( y in X or x = y ) ) )
thus
( {x,y} \ X = {x} implies ( not x in X & ( y in X or x = y ) ) )
( not x in X & ( y in X or x = y ) implies {x,y} \ X = {x} )
assume A3:
( not x in X & ( y in X or x = y ) )
; {x,y} \ X = {x}
for z being set holds
( z in {x,y} \ X iff z = x )
hence
{x,y} \ X = {x}
by TARSKI:def 1; verum