let a, b, c be real number ; ( a <= b iff c - b <= c - a )
hereby ( c - b <= c - a implies a <= b )
assume A1:
a <= b
;
not c - a < c - bassume
c - a < c - b
;
contradictionthen
- (c - b) < - (c - a)
by Lm15;
then
b - c < a - c
;
hence
contradiction
by A1, Lm7;
verum
end;
assume
c - a >= c - b
; a <= b
then
- (c - a) <= - (c - b)
by Lm14;
then
a - c <= b - c
;
hence
a <= b
by Th11; verum