let A be Ordinal; RelIncl A is well_founded
let Y be set ; WELLORD1:def 2 ( not Y c= field (RelIncl A) or Y = {} or ex b1 being set st
( b1 in Y & (RelIncl A) -Seg b1 misses Y ) )
assume that
A1:
Y c= field (RelIncl A)
and
A2:
Y <> {}
; ex b1 being set st
( b1 in Y & (RelIncl A) -Seg b1 misses Y )
defpred S1[ set ] means $1 in Y;
set x = the Element of Y;
A3:
field (RelIncl A) = A
by Def1;
then
the Element of Y in A
by A1, A2, TARSKI:def 3;
then reconsider x = the Element of Y as Ordinal ;
x in Y
by A2;
then A4:
ex B being Ordinal st S1[B]
;
consider B being Ordinal such that
A5:
( S1[B] & ( for C being Ordinal st S1[C] holds
B c= C ) )
from ORDINAL1:sch 1(A4);
reconsider x = B as set ;
take
x
; ( x in Y & (RelIncl A) -Seg x misses Y )
thus
x in Y
by A5; (RelIncl A) -Seg x misses Y
set y = the Element of ((RelIncl A) -Seg x) /\ Y;
assume A6:
((RelIncl A) -Seg x) /\ Y <> {}
; XBOOLE_0:def 7 contradiction
then A7:
the Element of ((RelIncl A) -Seg x) /\ Y in Y
by XBOOLE_0:def 4;
then reconsider C = the Element of ((RelIncl A) -Seg x) /\ Y as Ordinal by A1, A3;
A8:
the Element of ((RelIncl A) -Seg x) /\ Y in (RelIncl A) -Seg x
by A6, XBOOLE_0:def 4;
then
[ the Element of ((RelIncl A) -Seg x) /\ Y,x] in RelIncl A
by WELLORD1:1;
then A9:
C c= B
by A1, A3, A5, A7, Def1;
A10:
the Element of ((RelIncl A) -Seg x) /\ Y <> x
by A8, WELLORD1:1;
B c= C
by A5, A7;
hence
contradiction
by A10, A9, XBOOLE_0:def 10; verum