let f, g be Function; :: thesis: ( f is one-to-one & g is one-to-one & ( for x1, x2 being set st x1 in dom g & x2 in (dom f) \ (dom g) holds
g . x1 <> f . x2 ) implies f +* g is one-to-one )

assume that
A1: f is one-to-one and
A2: g is one-to-one and
A3: for x1, x2 being set st x1 in dom g & x2 in (dom f) \ (dom g) holds
g . x1 <> f . x2 ; :: thesis: f +* g is one-to-one
now
let x11, x22 be set ; :: thesis: ( x11 in dom (f +* g) & x22 in dom (f +* g) & (f +* g) . x11 = (f +* g) . x22 implies x11 = x22 )
assume that
A4: x11 in dom (f +* g) and
A5: x22 in dom (f +* g) and
A6: (f +* g) . x11 = (f +* g) . x22 ; :: thesis: x11 = x22
A7: x22 in (dom f) \/ (dom g) by A5, FUNCT_4:def 1;
then A8: x22 in ((dom f) \ (dom g)) \/ (dom g) by XBOOLE_1:39;
A9: x11 in (dom f) \/ (dom g) by A4, FUNCT_4:def 1;
then A10: x11 in ((dom f) \ (dom g)) \/ (dom g) by XBOOLE_1:39;
now end;
hence x11 = x22 ; :: thesis: verum
end;
hence f +* g is one-to-one by FUNCT_1:def 4; :: thesis: verum