let n be Ordinal; for T being connected TermOrder of n
for b1, b2 being bag of n holds
( min (b1,b2,T) = min (b2,b1,T) & max (b1,b2,T) = max (b2,b1,T) )
let T be connected TermOrder of n; for b1, b2 being bag of n holds
( min (b1,b2,T) = min (b2,b1,T) & max (b1,b2,T) = max (b2,b1,T) )
let b1, b2 be bag of n; ( min (b1,b2,T) = min (b2,b1,T) & max (b1,b2,T) = max (b2,b1,T) )
now per cases
( min (b1,b2,T) = b1 or min (b1,b2,T) <> b1 )
;
case A1:
min (
b1,
b2,
T)
= b1
;
min (b1,b2,T) = min (b2,b1,T)hence
min (
b1,
b2,
T)
= min (
b2,
b1,
T)
;
verum end; case A3:
min (
b1,
b2,
T)
<> b1
;
min (b1,b2,T) = min (b2,b1,T)A4:
now assume
not
b2 <= b1,
T
;
contradictionthen
b1 <= b2,
T
by Lm5;
hence
contradiction
by A3, Def4;
verum end; thus min (
b1,
b2,
T) =
b2
by A3, Th11
.=
min (
b2,
b1,
T)
by A4, Def4
;
verum end; end; end;
hence
min (b1,b2,T) = min (b2,b1,T)
; max (b1,b2,T) = max (b2,b1,T)
now per cases
( max (b1,b2,T) = b1 or max (b1,b2,T) <> b1 )
;
case A5:
max (
b1,
b2,
T)
= b1
;
max (b1,b2,T) = max (b2,b1,T)hence
max (
b1,
b2,
T)
= max (
b2,
b1,
T)
;
verum end; case A7:
max (
b1,
b2,
T)
<> b1
;
max (b2,b1,T) = max (b1,b2,T)hence
max (
b2,
b1,
T)
= max (
b1,
b2,
T)
;
verum end; end; end;
hence
max (b1,b2,T) = max (b2,b1,T)
; verum