let n be Ordinal; for T being TermOrder of n
for b being bag of n holds
( min (b,b,T) = b & max (b,b,T) = b )
let T be TermOrder of n; for b being bag of n holds
( min (b,b,T) = b & max (b,b,T) = b )
let b be bag of n; ( min (b,b,T) = b & max (b,b,T) = b )
thus
min (b,b,T) = b
by Def4; max (b,b,T) = b
thus
max (b,b,T) = b
by Def5; verum