let r, e be Real; ( 0 < r & 0 < e implies ex n being Element of NAT st
for m being Element of NAT st n <= m holds
for x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e )
assume that
A1:
0 < r
and
A2:
0 < e
; ex n being Element of NAT st
for m being Element of NAT st n <= m holds
for x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e
consider M, L being Real such that
A3:
( M >= 0 & L >= 0 )
and
A4:
for n being Element of NAT
for x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . n) . (s * x)) * (x |^ n)) / (n !)) <= (M * (L |^ n)) / (n !)
by A1, Th11;
consider n being Element of NAT such that
A5:
for m being Element of NAT st n <= m holds
(M * (L |^ m)) / (m !) < e
by A2, A3, Th12;
take
n
; for m being Element of NAT st n <= m holds
for x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e
let m be Element of NAT ; ( n <= m implies for x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e )
assume
n <= m
; for x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e
then A6:
(M * (L |^ m)) / (m !) < e
by A5;
let x, s be Real; ( x in ].(- r),r.[ & 0 < s & s < 1 implies abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e )
assume
( x in ].(- r),r.[ & 0 < s & s < 1 )
; abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e
then
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) <= (M * (L |^ m)) / (m !)
by A4;
hence
abs (((((diff (exp_R,].(- r),r.[)) . m) . (s * x)) * (x |^ m)) / (m !)) < e
by A6, XXREAL_0:2; verum