let n be Element of NAT ; for r, x, s being Real st x in ].(- r),r.[ & 0 < s & s < 1 holds
abs (((((diff (exp_R,].(- r),r.[)) . (n + 1)) . (s * x)) * (x |^ (n + 1))) / ((n + 1) !)) <= ((abs (exp_R . (s * x))) * ((abs x) |^ (n + 1))) / ((n + 1) !)
let r, x, s be Real; ( x in ].(- r),r.[ & 0 < s & s < 1 implies abs (((((diff (exp_R,].(- r),r.[)) . (n + 1)) . (s * x)) * (x |^ (n + 1))) / ((n + 1) !)) <= ((abs (exp_R . (s * x))) * ((abs x) |^ (n + 1))) / ((n + 1) !) )
assume that
A1:
x in ].(- r),r.[
and
A2:
0 < s
and
A3:
s < 1
; abs (((((diff (exp_R,].(- r),r.[)) . (n + 1)) . (s * x)) * (x |^ (n + 1))) / ((n + 1) !)) <= ((abs (exp_R . (s * x))) * ((abs x) |^ (n + 1))) / ((n + 1) !)
A4: abs ((s * x) - 0) =
(abs s) * (abs x)
by COMPLEX1:65
.=
s * (abs x)
by A2, ABSVALUE:def 1
;
x in ].(0 - r),(0 + r).[
by A1;
then A5:
abs (x - 0) < r
by RCOMP_1:1;
abs x >= 0
by COMPLEX1:46;
then
(abs x) * s < r * 1
by A2, A3, A5, XREAL_1:97;
then
s * x in ].(0 - r),(0 + r).[
by A4, RCOMP_1:1;
then A6:
s * x in dom (exp_R | ].(- r),r.[)
by Th5;
(n + 1) ! > 0
by NEWTON:17;
then A7:
abs ((n + 1) !) = (n + 1) !
by ABSVALUE:def 1;
abs (((((diff (exp_R,].(- r),r.[)) . (n + 1)) . (s * x)) * (x |^ (n + 1))) / ((n + 1) !)) =
abs ((((exp_R | ].(- r),r.[) . (s * x)) * (x |^ (n + 1))) / ((n + 1) !))
by Th6
.=
abs (((exp_R . (s * x)) * (x |^ (n + 1))) / ((n + 1) !))
by A6, FUNCT_1:47
.=
(abs ((exp_R . (s * x)) * (x |^ (n + 1)))) / (abs ((n + 1) !))
by COMPLEX1:67
.=
((abs (exp_R . (s * x))) * (abs (x |^ (n + 1)))) / ((n + 1) !)
by A7, COMPLEX1:65
;
hence
abs (((((diff (exp_R,].(- r),r.[)) . (n + 1)) . (s * x)) * (x |^ (n + 1))) / ((n + 1) !)) <= ((abs (exp_R . (s * x))) * ((abs x) |^ (n + 1))) / ((n + 1) !)
by Th1; verum