let SAS be Semi_Affine_Space; for a, b, c being Element of SAS st congr a,a,b,c holds
b = c
let a, b, c be Element of SAS; ( congr a,a,b,c implies b = c )
assume
congr a,a,b,c
; b = c
then
( ( a = a & b = c ) or ex p, q being Element of SAS st
( parallelogram p,q,a,a & parallelogram p,q,b,c ) )
by Def4;
hence
b = c
by Th54; verum