let z1, z2 be set ; ( ( for y1, y2, y3, y4, y5 being set st x = [y1,y2,y3,y4,y5] holds
z1 = y1 ) & ( for y1, y2, y3, y4, y5 being set st x = [y1,y2,y3,y4,y5] holds
z2 = y1 ) implies z1 = z2 )
assume that
A2:
for y1, y2, y3, y4, y5 being set st x = [y1,y2,y3,y4,y5] holds
z1 = y1
and
A3:
for y1, y2, y3, y4, y5 being set st x = [y1,y2,y3,y4,y5] holds
z2 = y1
; z1 = z2
z1 = x1
by A1, A2;
hence
z1 = z2
by A1, A3; verum