let z be set ; ( ex a, b, c, d being set st z = [a,b,c,d] implies z = [(z `1_4),(z `2_4),(z `3_4),(z `4_4)] )
given a, b, c, d being set such that A1:
z = [a,b,c,d]
; z = [(z `1_4),(z `2_4),(z `3_4),(z `4_4)]
A2:
z `3_4 = c
by A1, Def6;
( z `1_4 = a & z `2_4 = b )
by A1, Def4, Def5;
hence
z = [(z `1_4),(z `2_4),(z `3_4),(z `4_4)]
by A1, A2, Def7; verum