let P1, P2 be Probability of COM (Sigma,P); ( ( for B being set st B in Sigma holds
for C being thin of P holds P1 . (B \/ C) = P . B ) & ( for B being set st B in Sigma holds
for C being thin of P holds P2 . (B \/ C) = P . B ) implies P1 = P2 )
assume that
A82:
for B being set st B in Sigma holds
for C being thin of P holds P1 . (B \/ C) = P . B
and
A83:
for B being set st B in Sigma holds
for C being thin of P holds P2 . (B \/ C) = P . B
; P1 = P2
for x being set st x in COM (Sigma,P) holds
P1 . x = P2 . x
proof
let x be
set ;
( x in COM (Sigma,P) implies P1 . x = P2 . x )
assume
x in COM (
Sigma,
P)
;
P1 . x = P2 . x
then consider B being
set such that A84:
(
B in Sigma & ex
C being
thin of
P st
x = B \/ C )
by Def5;
P1 . x =
P . B
by A82, A84
.=
P2 . x
by A83, A84
;
hence
P1 . x = P2 . x
;
verum
end;
hence
P1 = P2
by FUNCT_2:12; verum