let b, a be ordinal number ; for n being natural number st 0 in n & n in b holds
b -exponent (n *^ (exp (b,a))) = a
let n be natural number ; ( 0 in n & n in b implies b -exponent (n *^ (exp (b,a))) = a )
assume A1:
( 0 in n & n in b )
; b -exponent (n *^ (exp (b,a))) = a
then A2:
succ 0 c= n
by ORDINAL1:21;
then A3:
( 1 *^ (exp (b,a)) = exp (b,a) & 1 *^ (exp (b,a)) c= n *^ (exp (b,a)) )
by ORDINAL2:39, ORDINAL2:41;
A4:
( exp (b,a) <> 0 & n <> 0 )
by A1, ORDINAL4:22;
then
0 <> n *^ (exp (b,a))
by ORDINAL3:31;
then A5:
( 1 in b & 0 in n *^ (exp (b,a)) )
by A2, A1, ORDINAL1:12, ORDINAL3:8;
now let c be
ordinal number ;
( exp (b,c) c= n *^ (exp (b,a)) implies not c c/= a )assume A6:
(
exp (
b,
c)
c= n *^ (exp (b,a)) &
c c/= a )
;
contradictionthen
a in c
by ORDINAL1:16;
then
succ a c= c
by ORDINAL1:21;
then A7:
exp (
b,
(succ a))
c= exp (
b,
c)
by A1, ORDINAL4:27;
exp (
b,
(succ a))
= b *^ (exp (b,a))
by ORDINAL2:44;
then
b *^ (exp (b,a)) c= n *^ (exp (b,a))
by A6, A7, XBOOLE_1:1;
then
b c= n
by A4, ORDINAL3:35;
then
n in n
by A1;
hence
contradiction
;
verum end;
hence
b -exponent (n *^ (exp (b,a))) = a
by A3, A5, Def10; verum