defpred S1[ Nat] means for k, m being Nat st k <= m & m = [\($1 / 2)/] holds
$1 choose m >= $1 choose k;
A1:
(1 / 2) - 1 < 0
;
A2:
for n being Nat st S1[n] holds
S1[n + 1]
proof
let n be
Nat;
( S1[n] implies S1[n + 1] )
assume A3:
S1[
n]
;
S1[n + 1]
A4:
n in NAT
by ORDINAL1:def 12;
for
k,
m1 being
Nat st
k <= m1 &
m1 = [\((n + 1) / 2)/] holds
(n + 1) choose m1 >= (n + 1) choose k
proof
[\(n / 2)/] <= n / 2
by INT_1:def 6;
then
- [\(n / 2)/] >= - (n / 2)
by XREAL_1:24;
then A5:
(- [\(n / 2)/]) + (n + 1) >= (- (n / 2)) + (n + 1)
by XREAL_1:6;
set m =
[\(n / 2)/];
let k,
m1 be
Nat;
( k <= m1 & m1 = [\((n + 1) / 2)/] implies (n + 1) choose m1 >= (n + 1) choose k )
assume A6:
k <= m1
;
( not m1 = [\((n + 1) / 2)/] or (n + 1) choose m1 >= (n + 1) choose k )
set nk1 =
(n + 1) - k;
set l =
n - [\(n / 2)/];
reconsider m =
[\(n / 2)/] as
Element of
NAT by INT_1:53;
2
* n >= 1
* n
by XREAL_1:64;
then A7:
(
n / 2
>= [\(n / 2)/] &
(2 * n) / 2
>= n / 2 )
by INT_1:def 6, XREAL_1:72;
then A8:
n >= m
by XXREAL_0:2;
n - m = n -' m
by A7, XREAL_1:233, XXREAL_0:2;
then reconsider l =
n - [\(n / 2)/] as
Element of
NAT ;
((n + 1) !) / (n !) =
((n + 1) * (n !)) / (n !)
by NEWTON:15
.=
(n + 1) * ((n !) / (n !))
by XCMPLX_1:74
.=
(n + 1) * 1
by XCMPLX_1:60
;
then A9:
(n !) / ((n + 1) !) = 1
/ (n + 1)
by XCMPLX_1:57;
A10:
(- (n / 2)) + (n + 1) = (n / 2) + 1
;
set nk =
n - k;
set l1 =
(n + 1) -' m1;
A11:
1
* m1 <= 2
* m1
by XREAL_1:64;
assume A12:
m1 = [\((n + 1) / 2)/]
;
(n + 1) choose m1 >= (n + 1) choose k
then
m1 <= (n + 1) / 2
by INT_1:def 6;
then A13:
m1 * 2
<= ((n + 1) / 2) * 2
by XREAL_1:64;
then A14:
(
n + 1
>= m1 &
(n + 1) -' m1 = (n + 1) - m1 )
by A11, XREAL_1:233, XXREAL_0:2;
A15:
(n + 1) / 2
>= [\((n + 1) / 2)/]
by INT_1:def 6;
A16:
n >= k
then
n - k = n -' k
by XREAL_1:233;
then reconsider nk =
n - k as
Element of
NAT ;
(n / 2) - 1
< [\(n / 2)/]
by INT_1:def 6;
then A17:
((n / 2) - 1) + 1
< [\(n / 2)/] + 1
by XREAL_1:6;
(n + 1) - k = nk + 1
;
then reconsider nk1 =
(n + 1) - k as
Element of
NAT ;
0 + n <= 1
+ n
by XREAL_1:6;
then A18:
k <= n + 1
by A16, XXREAL_0:2;
then A19:
(n + 1) choose k = ((n + 1) !) / ((nk1 !) * (k !))
by NEWTON:def 3;
A20:
(nk1 !) / (nk !) =
((nk + 1) * (nk !)) / (nk !)
by NEWTON:15
.=
(nk + 1) * ((nk !) / (nk !))
by XCMPLX_1:74
.=
(nk + 1) * 1
by XCMPLX_1:60
;
n choose k = (n !) / ((nk !) * (k !))
by A16, NEWTON:def 3;
then (n choose k) / ((n + 1) choose k) =
((n !) / ((nk !) * (k !))) / (((n + 1) !) / ((nk1 !) * (k !)))
by A18, NEWTON:def 3
.=
(((n !) / ((nk !) * (k !))) / ((n + 1) !)) * ((nk1 !) * (k !))
by XCMPLX_1:82
.=
((n !) / (((n + 1) !) * ((nk !) * (k !)))) * ((nk1 !) * (k !))
by XCMPLX_1:78
.=
((1 / (n + 1)) / ((nk !) * (k !))) * ((nk1 !) * (k !))
by A9, XCMPLX_1:78
.=
(1 / (n + 1)) / (((nk !) * (k !)) / ((nk1 !) * (k !)))
by XCMPLX_1:82
.=
(1 / (n + 1)) / (((nk !) / (nk1 !)) / ((k !) / (k !)))
by XCMPLX_1:84
.=
(1 / (n + 1)) / (((nk !) / (nk1 !)) / 1)
by XCMPLX_1:60
.=
(1 / (n + 1)) / (1 / (nk + 1))
by A20, XCMPLX_1:57
.=
(1 * (nk + 1)) / (1 * (n + 1))
by XCMPLX_1:84
.=
(nk + 1) / (n + 1)
;
then A21:
(n choose k) / (((n + 1) choose k) / ((n + 1) choose k)) = ((nk + 1) / (n + 1)) * ((n + 1) choose k)
by XCMPLX_1:82;
A22:
n choose k =
(n choose k) / 1
.=
((nk + 1) / (n + 1)) * ((n + 1) choose k)
by A19, A21, XCMPLX_1:60
;
then A23:
(n choose k) * ((n + 1) / (l + 1)) =
((((nk + 1) / (n + 1)) * ((n + 1) choose k)) * (n + 1)) / (l + 1)
by XCMPLX_1:74
.=
((((nk + 1) / (n + 1)) * (n + 1)) * ((n + 1) choose k)) / (l + 1)
.=
((((n + 1) / (n + 1)) * (nk + 1)) * ((n + 1) choose k)) / (l + 1)
by XCMPLX_1:75
.=
((1 * (nk + 1)) * ((n + 1) choose k)) / (l + 1)
by XCMPLX_1:60
.=
((n + 1) choose k) * ((nk + 1) / (l + 1))
by XCMPLX_1:74
;
A24:
(n choose k) * ((n + 1) / (m + 1)) =
((((nk + 1) / (n + 1)) * ((n + 1) choose k)) * (n + 1)) / (m + 1)
by A22, XCMPLX_1:74
.=
((((nk + 1) / (n + 1)) * (n + 1)) * ((n + 1) choose k)) / (m + 1)
.=
((((n + 1) / (n + 1)) * (nk + 1)) * ((n + 1) choose k)) / (m + 1)
by XCMPLX_1:75
.=
((1 * (nk + 1)) * ((n + 1) choose k)) / (m + 1)
by XCMPLX_1:60
.=
((n + 1) choose k) * ((nk + 1) / (m + 1))
by XCMPLX_1:74
;
per cases
( n is even or not n is even )
;
suppose
n is
even
;
(n + 1) choose m1 >= (n + 1) choose kthen consider k1 being
Element of
NAT such that A25:
n = 2
* k1
by A4, ABIAN:def 2;
A26:
[\((n + 1) / 2)/] =
[\(((2 * k1) / 2) + (1 / 2))/]
by A25
.=
k1 + [\(1 / 2)/]
by INT_1:28
.=
k1 + 0
by A1, INT_1:def 6
.=
[\(n / 2)/]
by A25, INT_1:25
;
then A27:
n choose m >= n choose k
by A3, A6, A12;
- k >= - [\(n / 2)/]
by A6, A12, A26, XREAL_1:24;
then
(- k) + (n + 1) >= (- [\(n / 2)/]) + (n + 1)
by XREAL_1:6;
then
((n - k) + 1) / ((n - [\(n / 2)/]) + 1) >= ((n - [\(n / 2)/]) + 1) / ((n - [\(n / 2)/]) + 1)
by A5, A10, XREAL_1:72;
then
((n - k) + 1) / ((n - [\(n / 2)/]) + 1) >= 1
by A5, A10, XCMPLX_1:60;
then A28:
(((n - k) + 1) / ((n - [\(n / 2)/]) + 1)) * ((n + 1) choose k) >= 1
* ((n + 1) choose k)
by XREAL_1:64;
A29:
(n + 1) -' m1 =
(n + 1) - m1
by A13, A11, XREAL_1:233, XXREAL_0:2
.=
l + 1
by A12, A26
;
(n + 1) choose m1 =
((n + 1) !) / ((m1 !) * (((n + 1) -' m1) !))
by A14, NEWTON:def 3
.=
((n + 1) * (n !)) / ((m !) * ((l + 1) !))
by A12, A26, A29, NEWTON:15
.=
((n + 1) * (n !)) / ((m !) * ((l + 1) * (l !)))
by NEWTON:15
.=
((n + 1) * (n !)) / ((l + 1) * ((m !) * (l !)))
.=
((n + 1) / (l + 1)) / (((m !) * (l !)) / (n !))
by XCMPLX_1:84
.=
((n !) / ((m !) * (l !))) * ((n + 1) / (l + 1))
by XCMPLX_1:80
.=
(n choose m) * ((n + 1) / (l + 1))
by A8, NEWTON:def 3
;
then
(n + 1) choose m >= ((n + 1) choose k) * ((nk + 1) / (l + 1))
by A12, A23, A26, A27, XREAL_1:64;
hence
(n + 1) choose m1 >= (n + 1) choose k
by A12, A26, A28, XXREAL_0:2;
verum end; suppose
not
n is
even
;
(n + 1) choose m1 >= (n + 1) choose kthen consider j being
Integer such that A30:
n = (2 * j) + 1
by ABIAN:1;
A31:
[\((n + 1) / 2)/] =
(j + 0) + 1
by A30, INT_1:25
.=
(j + [\(1 / 2)/]) + 1
by A1, INT_1:def 6
.=
[\(j + (1 / 2))/] + 1
by INT_1:28
.=
[\(n / 2)/] + 1
by A30
;
A32:
(n + 1) -' m1 =
(n + 1) - m1
by A13, A11, XREAL_1:233, XXREAL_0:2
.=
l
by A12, A31
;
per cases
( k = m + 1 or k < m + 1 )
by A6, A12, A31, XXREAL_0:1;
suppose
k < m + 1
;
(n + 1) choose m1 >= (n + 1) choose kthen A33:
k <= m
by NAT_1:13;
then A34:
n choose m >= n choose k
by A3;
n / 2
>= [\(n / 2)/]
by INT_1:def 6;
then
(n / 2) * 2
>= [\(n / 2)/] * 2
by XREAL_1:64;
then
n - [\(n / 2)/] >= ([\(n / 2)/] * 2) - [\(n / 2)/]
by XREAL_1:9;
then
n - [\(n / 2)/] >= k
by A33, XXREAL_0:2;
then
(n - [\(n / 2)/]) - (k - [\(n / 2)/]) >= k - (k - [\(n / 2)/])
by XREAL_1:9;
then
(n - k) + 1
>= [\(n / 2)/] + 1
by XREAL_1:6;
then
((n - k) + 1) / ([\(n / 2)/] + 1) >= ([\(n / 2)/] + 1) / ([\(n / 2)/] + 1)
by A17, XREAL_1:72;
then
((n - k) + 1) / ([\(n / 2)/] + 1) >= 1
by A17, XCMPLX_1:60;
then A35:
(((n - k) + 1) / ([\(n / 2)/] + 1)) * ((n + 1) choose k) >= 1
* ((n + 1) choose k)
by XREAL_1:64;
(n + 1) choose m1 =
((n + 1) !) / ((m1 !) * (((n + 1) -' m1) !))
by A14, NEWTON:def 3
.=
((n + 1) * (n !)) / (((m + 1) !) * (l !))
by A12, A31, A32, NEWTON:15
.=
((n + 1) * (n !)) / (((m !) * (m + 1)) * (l !))
by NEWTON:15
.=
((n + 1) * (n !)) / ((m + 1) * ((m !) * (l !)))
.=
((n + 1) / (m + 1)) / (((m !) * (l !)) / (n !))
by XCMPLX_1:84
.=
((n !) / ((m !) * (l !))) * ((n + 1) / (m + 1))
by XCMPLX_1:80
.=
(n choose m) * ((n + 1) / (m + 1))
by A8, NEWTON:def 3
;
then
(n + 1) choose m1 >= ((n + 1) choose k) * ((nk + 1) / (m + 1))
by A24, A34, XREAL_1:64;
hence
(n + 1) choose m1 >= (n + 1) choose k
by A35, XXREAL_0:2;
verum end; end; end; end;
end;
hence
S1[
n + 1]
;
verum
end;
A36:
S1[ 0 ]
A38:
for n being Nat holds S1[n]
from NAT_1:sch 2(A36, A2);
for n, k, m being Nat st k <= n & m = [\(n / 2)/] holds
n choose m >= n choose k
proof
let n,
k,
m be
Nat;
( k <= n & m = [\(n / 2)/] implies n choose m >= n choose k )
A39:
n in NAT
by ORDINAL1:def 12;
assume A40:
k <= n
;
( not m = [\(n / 2)/] or n choose m >= n choose k )
assume A41:
m = [\(n / 2)/]
;
n choose m >= n choose k
per cases
( k <= m or k > m )
;
suppose A42:
k > m
;
n choose m >= n choose kset r =
n -' k;
A43:
n -' k = n - k
by A40, XREAL_1:233;
then A44:
n choose k = n choose (n -' k)
by A40, NEWTON:20;
per cases
( n is even or not n is even )
;
suppose
not
n is
even
;
n choose m >= n choose kthen consider j being
Integer such that A47:
n = (2 * j) + 1
by ABIAN:1;
A48:
k >= m + 1
by A42, NAT_1:13;
A49:
[\(n / 2)/] =
[\(j + (1 / 2))/]
by A47
.=
j + [\(1 / 2)/]
by INT_1:28
.=
j + 0
by A1, INT_1:def 6
.=
j
;
per cases
( k = m + 1 or k > m + 1 )
by A48, XXREAL_0:1;
suppose A50:
k = m + 1
;
n choose m >= n choose kset nm1 =
n - (m + 1);
set nm =
n - m;
2
* n >= 1
* n
by XREAL_1:64;
then A51:
(
n / 2
>= [\(n / 2)/] &
(2 * n) / 2
>= n / 2 )
by INT_1:def 6, XREAL_1:72;
then A52:
n >= m
by A41, XXREAL_0:2;
n - m = n -' m
by A41, A51, XREAL_1:233, XXREAL_0:2;
then reconsider nm =
n - m as
Element of
NAT ;
2
* m >= 1
* m
by XREAL_1:64;
then A53:
n >= m + 1
by A41, A47, A49, XREAL_1:6;
then
n - (m + 1) = n -' (m + 1)
by XREAL_1:233;
then reconsider nm1 =
n - (m + 1) as
Element of
NAT ;
A54:
n choose (m + 1) = (n !) / ((nm1 !) * ((m + 1) !))
by A53, NEWTON:def 3;
nm = m + 1
by A41, A47, A49;
hence
n choose m >= n choose k
by A50, A52, A54, NEWTON:def 3;
verum end; end; end; end; end; end;
end;
hence
for n, k, m being Nat st k <= n & m = [\(n / 2)/] holds
n choose m >= n choose k
; verum