let a, b, c, d be Element of Example; ( a @ a = a & a @ b = b @ a & (a @ b) @ (c @ d) = (a @ c) @ (b @ d) & ex x being Element of Example st x @ a = b )
thus a @ a =
{}
by CARD_1:49, TARSKI:def 1
.=
a
by CARD_1:49, TARSKI:def 1
; ( a @ b = b @ a & (a @ b) @ (c @ d) = (a @ c) @ (b @ d) & ex x being Element of Example st x @ a = b )
thus a @ b =
{}
by CARD_1:49, TARSKI:def 1
.=
b @ a
by CARD_1:49, TARSKI:def 1
; ( (a @ b) @ (c @ d) = (a @ c) @ (b @ d) & ex x being Element of Example st x @ a = b )
thus (a @ b) @ (c @ d) =
{}
by CARD_1:49, TARSKI:def 1
.=
(a @ c) @ (b @ d)
by CARD_1:49, TARSKI:def 1
; ex x being Element of Example st x @ a = b
take x = a; x @ a = b
thus x @ a =
{}
by CARD_1:49, TARSKI:def 1
.=
b
by CARD_1:49, TARSKI:def 1
; verum