let M be MidSp; for x, y, a, b, c, d being Element of M st x,y @@ a,b & x,y @@ c,d holds
a,b @@ c,d
let x, y, a, b, c, d be Element of M; ( x,y @@ a,b & x,y @@ c,d implies a,b @@ c,d )
assume A1:
x,y @@ a,b
; ( not x,y @@ c,d or a,b @@ c,d )
assume A2:
x,y @@ c,d
; a,b @@ c,d
(y @ x) @ (a @ d) =
(y @ a) @ (x @ d)
by Def4
.=
(x @ b) @ (x @ d)
by A1, Def5
.=
(x @ b) @ (y @ c)
by A2, Def5
.=
(y @ x) @ (b @ c)
by Def4
;
hence
a @ d = b @ c
by Th18; MIDSP_1:def 4 verum