let X be set ; for S being SigmaField of X
for M being sigma_Measure of S
for F being Function of NAT,S st ( for n being Element of NAT holds F . (n + 1) c= F . n ) & M . (F . 0) < +infty holds
M . (meet (rng F)) = inf (rng (M * F))
let S be SigmaField of X; for M being sigma_Measure of S
for F being Function of NAT,S st ( for n being Element of NAT holds F . (n + 1) c= F . n ) & M . (F . 0) < +infty holds
M . (meet (rng F)) = inf (rng (M * F))
let M be sigma_Measure of S; for F being Function of NAT,S st ( for n being Element of NAT holds F . (n + 1) c= F . n ) & M . (F . 0) < +infty holds
M . (meet (rng F)) = inf (rng (M * F))
let F be Function of NAT,S; ( ( for n being Element of NAT holds F . (n + 1) c= F . n ) & M . (F . 0) < +infty implies M . (meet (rng F)) = inf (rng (M * F)) )
assume that
A1:
for n being Element of NAT holds F . (n + 1) c= F . n
and
A2:
M . (F . 0) < +infty
; M . (meet (rng F)) = inf (rng (M * F))
consider G being Function of NAT,S such that
A3:
( G . 0 = {} & ( for n being Element of NAT holds G . (n + 1) = (F . 0) \ (F . n) ) )
by MEASURE2:9;
A4:
union (rng G) = (F . 0) \ (meet (rng F))
by A1, A3, Th6;
A5:
M . ((F . 0) \ (union (rng G))) = M . (meet (rng F))
by A1, A3, Th7;
A6:
for A being Element of S st A = union (rng G) holds
M . (meet (rng F)) = (M . (F . 0)) - (M . A)
for n being Element of NAT holds G . n c= G . (n + 1)
by A1, A3, MEASURE2:13;
then
M . (union (rng G)) = sup (rng (M * G))
by MEASURE2:23;
then
M . (meet (rng F)) = (M . (F . 0)) - (sup (rng (M * G)))
by A6;
hence
M . (meet (rng F)) = inf (rng (M * F))
by A1, A2, A3, Th13; verum