let X1, X2, X3, X4, X5 be set ; ( X1 <> {} & X2 <> {} & X3 <> {} & X4 <> {} & X5 <> {} implies for x being Element of [:X1,X2,X3,X4,X5:] ex xx1 being Element of X1 ex xx2 being Element of X2 ex xx3 being Element of X3 ex xx4 being Element of X4 ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5] )
assume that
A1:
( X1 <> {} & X2 <> {} & X3 <> {} & X4 <> {} )
and
A2:
X5 <> {}
; for x being Element of [:X1,X2,X3,X4,X5:] ex xx1 being Element of X1 ex xx2 being Element of X2 ex xx3 being Element of X3 ex xx4 being Element of X4 ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5]
let x be Element of [:X1,X2,X3,X4,X5:]; ex xx1 being Element of X1 ex xx2 being Element of X2 ex xx3 being Element of X3 ex xx4 being Element of X4 ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5]
reconsider x9 = x as Element of [:[:X1,X2,X3,X4:],X5:] ;
[:X1,X2,X3,X4:] <> {}
by A1, MCART_1:51;
then consider x1234 being Element of [:X1,X2,X3,X4:], xx5 being Element of X5 such that
A3:
x9 = [x1234,xx5]
by A2, Lm1;
consider xx1 being Element of X1, xx2 being Element of X2, xx3 being Element of X3, xx4 being Element of X4 such that
A4:
x1234 = [xx1,xx2,xx3,xx4]
by A1, Lm3;
take
xx1
; ex xx2 being Element of X2 ex xx3 being Element of X3 ex xx4 being Element of X4 ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5]
take
xx2
; ex xx3 being Element of X3 ex xx4 being Element of X4 ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5]
take
xx3
; ex xx4 being Element of X4 ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5]
take
xx4
; ex xx5 being Element of X5 st x = [xx1,xx2,xx3,xx4,xx5]
take
xx5
; x = [xx1,xx2,xx3,xx4,xx5]
thus
x = [xx1,xx2,xx3,xx4,xx5]
by A3, A4; verum