let n be Nat; for K being Field
for M being Matrix of n,K st M is invertible & n > 0 holds
(M @) ~ = (M ~) @
let K be Field; for M being Matrix of n,K st M is invertible & n > 0 holds
(M @) ~ = (M ~) @
let M be Matrix of n,K; ( M is invertible & n > 0 implies (M @) ~ = (M ~) @ )
assume that
A1:
M is invertible
and
A2:
n > 0
; (M @) ~ = (M ~) @
set M1 = M @ ;
set M2 = (M ~) @ ;
A3:
( width M = n & width (M ~) = n )
by MATRIX_1:24;
len M = n
by MATRIX_1:24;
then A4:
((M ~) * M) @ = (M @) * ((M ~) @)
by A2, A3, MATRIX_3:22;
A5:
M ~ is_reverse_of M
by A1, Def4;
then
(M ~) * M = 1. (K,n)
by Def2;
then A6:
(M @) * ((M ~) @) = 1. (K,n)
by A4, Th10;
len (M ~) = n
by MATRIX_1:24;
then
(M * (M ~)) @ = ((M ~) @) * (M @)
by A2, A3, MATRIX_3:22;
then
(M @) * ((M ~) @) = ((M ~) @) * (M @)
by A5, A4, Def2;
then A7:
M @ is_reverse_of (M ~) @
by A6, Def2;
then
M @ is invertible
by Def3;
hence
(M @) ~ = (M ~) @
by A7, Def4; verum