let X1, X2 be Element of F1(); ( ( for x being set holds
( x in X1 iff P1[x] ) ) & ( for x being set holds
( x in X2 iff P1[x] ) ) implies X1 = X2 )
assume that
A1:
for x being set holds
( x in X1 iff P1[x] )
and
A2:
for x being set holds
( x in X2 iff P1[x] )
; X1 = X2
now let x be
set ;
( x in X1 iff x in X2 )
(
x in X1 iff
P1[
x] )
by A1;
hence
(
x in X1 iff
x in X2 )
by A2;
verum end;
hence
X1 = X2
by TARSKI:1; verum